Draw Rectangle from Webcam with 2 largest object
I need to draw rectangle with 2 largest object from webcam. I already got to draw contours with 2 largest object from webcam but now i confuse in how to draw 2 largest Rectangle. Someone can show me the code Please~
//find and draw contours
void showconvex(Mat &thresh,Mat &frame)
{
int largestIndex = 0;
int largestContour = 0;
int secondLargestIndex = 0;
int secondLargestContour = 0;
vector<vector<Point> > contours;
vector<Vec4i> hierarchy;
//find contours
findContours(thresh, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE);
/// Find the convex hull object for each contour
vector<vector<Point> >hull(contours.size());
vector<vector<int> >inthull(contours.size());
vector<vector<Vec4i> >defects(contours.size());
for (int i = 0; i < contours.size(); i++)
{
convexHull(Mat(contours[i]), hull[i], false);
convexHull(Mat(contours[i]),inthull[i], false);
if (inthull[i].size()>3)
convexityDefects(contours[i], inthull[i], defects[i]);
}
//find 2 largest contour
for( int i = 0; i< contours.size(); i++ )
{
if(contours[i].size() > largestContour)
{
secondLargestContour = largestContour;
secondLargestIndex = largestIndex;
largestContour = contours[i].size();
largestIndex = i;
}
else if(contours[i].size() > secondLargestContour)
{
secondLargestContour = contours[i].size();
secondLargestIndex = i;
}
}
//show contours of 2 biggest and hull as well
if(contours.size()>0)
{
//check for contouraea function if error occur
//draw the 2 largest contour using previously stored index.
drawContours(frame, contours, largestIndex, CV_RGB(0,255,0), 2, 8, hierarchy);
drawContours(frame, contours, secondLargestIndex, CV_RGB(0,255,0), 2, 8, hierarchy);
}
}
Do you want to draw a rectangle around your largest contours or do you want to recognize if your contours are (approximate?) rectangles? To estimate and draw rectangles: http://docs.opencv.org/2.4/doc/tutori...
yeah , i only want draw rectangles around 2 largest contour only. Please help me -w-
Then just have a look at the link I posted.