I am trying to copy a vector of Point2f's into a vector of Point2d's. I am unable to directly cast the Point2f elements to Point2d, as in:
for (int i = 0 ; i < (int)vector1.size() ; i++)
{
vector2.push_back((cv::Point2d)vector1[i]);
}
The usual std way does not work either.
Example: std::vector<cv::Point2d> vector2(vector1.begin(), vector1.end());
If that code does not work, which actually should work like @LBerger pointed out, you could try to break it down a bit more, like the following code.
vector<Point2f> vector1;
vector<Point2d> vector2;
for (size_t i=0 ; i<vector1.size(); i++)
{
vector2.push_back( cv::Point2d( (double)vector1[i].x, (double)vector1[i].y ) );
}
Which works just fine over here also.
Why would you want to do this? This is a giant overhead of parsing each vector into a new mat format? ...
It is possible that casting for OpenCV specific types is not enabled ... @LBerger, you did nothing special or extra to get that to work? Should dig deeper in this.
My results : [10, 0; 5, 1; 3.333333333333334, 2] [10, 0; 5, 1; 3.3333333, 2] [10, 0; 5, 1; 3.3333333, 2]
with this program so
vector<Point2d> vd;
vector<Point2f> vf;
for (int i=0;i<3;i++)
vd.push_back(Point2d(10.0/(i+1),i));
for (int i = 0; i < vd.size(); i++)
{
Point2f p=vd[i];
vf.push_back(vd[i]);
}
cout<<vd<<"\n";
cout<<vf<<"\n";
std::vector<cv::Point2f> vector2(vd.begin(), vd.end());
cout << vector2 << "\n";
May be I miss something (VS2013 windows 10 64bits)
Oh thats implicit type conversion, by forcing one type into the other. That is different than explicit typecasting like he suggested, which does not work --> (cv::Point2d)vector1[i])
I have made this test too and it's OK
for (int i = 0; i < vd.size(); i++)
{
Point2f p=vd[i];
vf.push_back((cv::Point2f)vd[i]);
}
in debug mode I can see this call opencv2\core\types.hpp line 1089 and for this test too :
for (int i = 0; i < vd.size(); i++)
{
Point2f p=vd[i];
vf.push_back(vd[i]);
}
That only works because you have the line Point2f p=vd[i];. Basically OpenCV uses smart pointers and there you redefine the pointer interface to the item in question. Then ofcourse the pushing will work. Could you test if
for (int i = 0; i < vd.size(); i++)
{
vf.push_back((Point2f)vd[i]);
}
works. I am guessing it does not.
My test is now
vector<Point2d> vd;
vector<Point2f> vf;
for (int i=0;i<3;i++)
vd.push_back(Point2d(10.0/(i+1),i));
for (int i = 0; i < vd.size(); i++)
{
vf.push_back(vd[i]);
}
cout<<"vd ="<<vd<<"\n";
cout<<"vf = "<<vf<<"\n";
std::vector<cv::Point2f> vector2(vd.begin(), vd.end());
cout <<"vector 2="<< vector2 << "\n";
Results :
vd =[10, 0;
5, 1;
3.333333333333334, 2]
vf = [10, 0;
5, 1;
3.3333333, 2]
vector 2=[10, 0;
5, 1;
3.3333333, 2]
Asked: 2015-08-09 16:48:14 -0600
Seen: 19,477 times
Last updated: Aug 10 '15
I don't undestand your problem. Ihave try your example it works for me. What is your configuration opencv, pc ide..?
That's strange. I am using 2.4.11 on linux with cmake. It says "Call of overloaded Point_(cv::Point_<float>&) is ambiguous."
Either way, treating it as a Mat worked for me: cv::Mat(vector1).convertTo(vector2, cv::Mat(vector2).type())