I have this function:
bool interpolate(const Mat &im, float ofsx, float ofsy, float a11, float a12, float a21, float a22, Mat &res)
{
// input size (-1 for the safe bilinear interpolation)
const int width = im.cols-1;
const int height = im.rows-1;
// output size
const int halfWidth = res.cols >> 1;
const int halfHeight = res.rows >> 1;
float *out = res.ptr<float>(0);
const float *imptr = im.ptr<float>(0);
const float *resptr = im.ptr<float>(0);
for (int j=-halfHeight; j<=halfHeight; ++j)
{
//...
for(int i=-halfWidth; i<=halfWidth; ++i, out++)
{
const int x = (int) //something;
const int y = (int) //something;
if (x >= 0 && y >= 0 && x < width && y < height)
{
std::cout<<"im(y,x)="<<im.at<float>(y,x)<<" imptr[y*width+x]="<<imptr[y*width+x]<<std::endl;
}
}
}
return ret;
}
Where I want to use const float *imptr
instead of const cv::Mat img
for better efficiency. However, I can't understand why, but imptr[y*width+x]!=im.at<float>(y,x)
. Why?