when i draw the bounding box with centriod, i got the bounding box inside bounding box like this
Actually i want to ignore the inner bounding box in all my bounding box.
I am using below code with ignoring all circles. link
You can change findcontour() mode parameter to CV_RETR_EXTERNAL which will retrieves only the extreme outer contours, and sets hierarchy[i][2]=hierarchy[i][3]=-1 for all the contours. That is CV_RETR_EXTERNAL will exclude all child contour(contour inside contour).
And if your code need to extract all contour(including child) you can iterate through only outer contour(first hierarchy level) using below code,
for( int i = 0; i< contours.size(); i=hierarchy[i][0] ) // iterate through outer contour exclude child
Also see this question, might be helpful.
Well, thanks haris for a new concept(really useful), but i use Steven code ie
int cmin= 50;
int cmax= 1000;
vector<vector<Point> >::iterator itc=contours.begin();
while (itc!=contours.end()) {
if (itc->size() < cmin || itc->size() > cmax){
itc= contours.erase(itc);}
else{
vector<Point> pts = *itc;
Mat pointsMatrix = Mat(pts);
Scalar color( 0, 255, 0 );
Rect r0= boundingRect(pointsMatrix);
rectangle(threshold_output,r0,color,2);
above sample code will solve my issue. But @Haris and @steven thanks for immediate reply & good luck
Asked: 2014-03-31 07:23:55 -0600
Seen: 7,179 times
Last updated: Apr 02 '14
Just cross reference the corners with eachother. If the topleft corner of the smaller object has an x and y larger then topleft of the larger object AND it has an bottomright corner with an x and y value that is smaller than the x and y of the larger object, then you can simply remove the detection. Seems pretty feasible to me.
Ah confused, can you provide some link or code(rough code).
I find it very strange that you cannot solve this yourself or by the directions given. This is a basic mathematical problem... However @Haris gave you a good indication on how to solve your problem also if you do not want to do it during postprocessing!