Ask Your Question
0

Distance from an object.. Where is the camera origine?

asked 2017-04-13 08:45:43 -0600

ROSpioneer gravatar image

I compute the distance from an object (Chessboard) using OpenCv and my camera parameters using those steps:

findChessboardCorners

solvePnP

->Distance

The distance I get is between two points: the chessboard and the camera. My question is where is the origine of my camera?

I know perfectly about my Chessboard but not my camera in terms of reference.

edit retag flag offensive close merge delete

Comments

1

As far as I understand camera calibration, the camera origin is on the focal point, which is the projection center. This topic has nice figure illustrating this. So my guess is that the distance is between the object point (your pattern position) and the projection center. @Tetragramm has the necessary experience to confirm this I guess.

StevenPuttemans gravatar imageStevenPuttemans ( 2017-04-14 04:52:11 -0600 )edit

1 answer

Sort by ยป oldest newest most voted
1

answered 2017-04-14 16:55:49 -0600

Tetragramm gravatar image

I'm not actually sure (I haven't been in a situation where it mattered), but I believe that it is the point of convergence in the lens system. In other words, centered in the lens, 1 focal length in front of the focal plane.

There's an image HERE that shows things nicely, but I don't know if there's still abstraction going on here.

It might also be 1 focal length in behind that point, along the optical axis, which would be the where the optical axis intersects the focal plane, but I don't think so.

edit flag offensive delete link more

Question Tools

1 follower

Stats

Asked: 2017-04-13 08:45:43 -0600

Seen: 337 times

Last updated: Apr 14 '17