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I hate this method for finding points it doesn't take in to account the size of the image. And makes obvious translations way harder.
Instead I recommend solving for X given Y or Y given X
Y = (rho - aX)/b
X= (rho - bX)/a
(Where a = cos(theta) and b = sin(theta)
Now just sub in the intersects you want to find
[fX(Y=0), fY(X=0) | fX(Y=image height), fY(X=image width)]
Better yet let's say you need to know where the line crosses in the middle of the screen. Now you have the formula.
