1 | initial version |
Hi Himanshu!
That seems about right. But if you are concerned about the execution speed, the following might be a bit faster (just extracted common operations out of the loop, a good compiler should be able to generate efficient loops for your code as well):
IplImage* bgr_frame = cvQueryFrame( capture );
int width, height, nchannels, step, offset;
int i, j, r_ch, b_ch, g_ch;
width = bgr_frame->width;
height = bgr_frame->height;
nchannels = bgr_frame->nChannels;
step = bgr_frame->widthStep;
for(i = 0 ; i < height ; i++)
{
uchar* data = (uchar*)(bgr_frame->imageData + i*step);
for( j = 0 ; j < width ; j++)
{
offset = j * nchannels;
b_ch = data[offset];
g_ch = data[offset + 1];
r_ch = data[offset + 2];
}
}
Cheers!
2 | added a comment on the code |
Hi Himanshu!
That seems about right. But if you are concerned about the execution speed, the following might be a bit faster (just extracted common operations out of the loop, a good compiler should be able to generate efficient loops for your code as well):
IplImage* bgr_frame = cvQueryFrame( capture );
int width, height, nchannels, step, offset;
int i, j, r_ch, b_ch, g_ch;
width = bgr_frame->width;
height = bgr_frame->height;
nchannels = bgr_frame->nChannels;
step = bgr_frame->widthStep;
for(i = 0 ; i < height ; i++)
{
uchar* data = (uchar*)(bgr_frame->imageData + i*step);
for( j = 0 ; j < width ; j++)
{
offset = j * nchannels;
nchannels; //You should make sure that nchannels is 3
b_ch = data[offset];
g_ch = data[offset + 1];
r_ch = data[offset + 2];
}
}
Cheers!